Is there any trivial way to 'delete by date' using ´rm'- in bash?

I noticed today (after ~8 years of happily hacking away at bash) that there is no trivial way to 'delete by date' using ´rm'. The solution is therefore to pipe stuff around a combination of commands like rm, ls, find, awk and sed.

Say for example I wanted to delete every file in the working directory from 2009, what would be a typical stackoverflowers approach?

I came up with the following, which is butt-ugly and should only be run if 'rm' is set to skip over directories (otherwise you will delete the parent directory):

ls -la | awk '{if (substr($6,0,5)==2009) print $8}' | xargs rm

Points for both the most elegant and the most outrageously over-engineered sloutions.

From stackoverflow

• I would combine find and rm (without pipe)

  find .  ...bunch of find criterias to select certain files (e.g. by date) .... -exec rm \{\} \;
  

  EDIT: with parameters for your example it would be

  find . -maxdepth 1 -type f -ctime -12 -exec rm \{\} \;
  

  CAVEAT: This works just today :-). (To make it work everytime, replace the -ctime with absoulte time, see timeXY in the manpage )

  OIS : Example here: http://www.howtogeek.com/howto/ubuntu/delete-files-older-than-x-days-on-linux/

  Rob Kennedy : Is there any danger of "rm" interpreting a file name as a command switch in this scenario, and thus deleting too little or too much?

  Joachim Sauer : @Rob: Partially: "-exec" calls rm with only one argument each time, so there's only the danger to delete too little. You could replace "rm \{\} \;" with "rm -- \{\} \;" to avoid that.

  Porges : `\{\}` is superfluous; just use `{}`

• find(1) is a much more efficient to do what you want than parsing ls(1) output.

  EDIT: something to watch for is filenames with spaces in them so you want to have a find which supports -print0 (to be used with xargs -0) for better performance.

  find . -mtime +12 -print0 | xargs -0 rm -f
  

• Instead of parsing ls(1) which can too easily break you should rely on stat(1):

  stat -c '%z/%n' files_or_glob | grep '^date' | cut -d/ -f2- | xargs -d '\n' rm -i
  

  e.g.

  $ stat -c '%z/%n' *| grep '^2008-12-16' | cut -d/ -f2- | xargs -d '\n' rm -i
  

  Note: this will not handle filenames with embedded newlines correctly. However they are rarely found in the wil.d

• Some versions of find support the -delete option, making it even more efficient...

  find . -maxdepth 1 -type f -ctime -12 -delete;
  

  Check your find man page (this has worked on most recent releases of Ubuntu for me)

  Fergie : nice- I like that there are no pipes or -execs

  Alastair : Nice, except that it doesn't use rm as required in the question. I'm not trolling: using rm is a valid requirement if, for example, you want to use -i for interactive delete...

• I would use:

  find . -maxdepth 1 -type f -newerct 'jan 1' -print0 \
      | xargs -0 rm
  

  (or -newermt if you want to filter on modification time)

  Note that the 't' form of -newerXY will allegedtly allow any date format compatible with cvs (see doco).